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[°øÁö] Àΰ ¼ö°»ý Ä«Ä«¿ÀÅå ÁúÀÇÀÀ´ä ¹æ¹ý |
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2021-05-20 |
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[°øÁö] Àΰ ¼ö°»ý Ä«Ä«¿ÀÅå ÁúÀÇÀÀ´ä ¹æ¹ý |
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2021-05-20 |
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Àΰ ¼ö°»ý ¿©·¯ºÐµé
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1. Ä«Ä«¿ÀÅå¿¡ ¼±»ý´Ô ¾ÆÀ̵ð Ãß°¡
ȫâÀÇ ¼±»ý´Ô Ä«Ä«¿ÀÅå ¾ÆÀ̵ð : hongdly
2. Áú¹®ÇÒ ¶§, º»ÀÎÀÌ ¼ö°ÇÏ°í ÀÖ´Â °ÀÇ¸í ±âÀç / ¸î °ÀÎÁö ±âÀçÇØÁֽñ⠹ٶø´Ï´Ù.
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2017-09-23 |
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¾È³çÇϼ¼¿ä ±³¼ö´Ô À̹ø¿¡ ±³¼ö´ÔÀÇ °ÀǸ¦ ¼ö°ÇÏ°Ô µÈ ÀÌ»ó¿øÀ̶ó°í ÇÕ´Ï´Ù. ´Ù¸§ÀÌ ¾Æ´Ï¶ó ÆíÀÔ¼öÇÐÀ» óÀ½ ½ÃÀÛÇÏ´Â µ¥ ±âÃÊÆíÀ» °Ç³Ê¶Ù°í ¹Ù·Î ¹ÌºÐÇÐ1ºÎÅÍ ¼ö°Çصµ ±¦ÂúÀºÁö ±Ã±ÝÇؼ ÀÌ·¸°Ô Áú¹® ³²±é´Ï´Ù. ÀúÀÇ ±âº» º£À̽º´Â ¼ö´É ¼öÇè»ý ½ÃÀý ¹®°ú¿´¾ú°í ¸ðÀÇ °í»ç¿¡¼ Ç×»ó 1µî±ÞÀÇ ¼ºÀû(92-96Á¡)À» À¯Áö ÇÏ¿´½À´Ï´Ù. ºñ·Ï ¼ö´ÉÀº ±×¸® Àߺ¸Áö ¸øÇÏ¿©¼ 3µî±ÞÀ» ¸Â¾Ò½À´Ï´Ù¸¸ 17¼ö´É ¿À´äÀ² 1À§ ¿´´ø 30¹ø ¹®Á¦¸¦ Ç®¾ú½À´Ï´Ù.
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2017-09-23 |
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2017-09-21 |
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dudehs10** |
µî·ÏÀÏ |
2017-09-21 |
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°³Á¤ÆÇ 193ÂÊ¿¡ ÆíµµÇÔ¼ö fx (0,y) = lim [f(h,y)-f(0,y) ]/h ¿¡¼¿ä f(0.y) À̸é f(x,y) ÇÔ¼ö xÀÚ¸®¿¡´Ù 0³Ö´Â °Å¾Æ´Ñ°¡¿ä? xÀÚ¸®¿¡ h°¡ ³ª¿ÍÀÖ½À´Ï´Ù f ¸¦ x·ÎÆí¹ÌºÐÇÑµÚ y·Î Æí¹ÌºÐÇϱâÀ§Çؼ f¸¦ x·Î Æí¹ÌºÐÇÑ°ª¿¡´Ù°¡ xÀÚ¸®¿¡ ½Ç¼öÀÇ°ªÀ» ´ëÀÔÇÑµÚ yÀÚ¸®¿¡´Â y·Î Æí¹ÌºÐÀ» ÇϱâÀ§ÇØ ¹ÌÁö¼ö·Î µÎ´Â°Í¿¡À־ ³ë¶õ»ö ÇʱâºÎºÐ±îÁö´Â ÀÌÇØ°¡ µÇ¾ú½À´Ï´Ù. ±Ù·±µ¥ µÚ¿¡ Èò»öºÎºÐ¿¡´Â -f(0,y) = -y^2 arctan (0/y)=0 Áï, 0ÀÌµÇ¾î¼ fx(0,y) Æí¹ÌºÐ Çѹø¸¸ ÇÑ°ªÀ¸·Î 0À̳ª¿Í 2°è Æí¹ÌºÐÀ» ÇÏ°ÔµÇ¸é ±×´ë·Î 2¹øÀÌ Á¤´äÀÌ¿©¾ß ÇÏÁö¾Ê³ª¿ä? yºÎÅÍ Æí¹ÌºÐÀ» ½ÃÀÛÇÏ¸é ¾ÕºÎºÐÀÌ x°¡ ³²°í µÞºÎºÐÀÌ 0À̵Ǿî ÃÖÁ¾ÀûÀ¸·Î x°¡³²°í ÀÌ°ÍÀ» ´Ù½Ã x·Î Æí¹ÌºÐÇϸé 1ÀÌ ³ª¿É´Ï´Ù ..
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2017-09-23 |
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´Ù½Ãº¸¼¼¿ä ±×·¸°Ô ¾²Áö ¾Ê¾Ò´Âµ¥¿ä. ´Ù½Ã È®ÀÎ ºÎŹ ÇÕ´Ï´Ù. ±×¸®°í tan^-1 h/y= h/y ·Î ³ª¿ÀÁÒ
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2017-09-20 |
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2017-09-20 |
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2017-09-21 |
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2017-09-19 |
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58p °ã°è½Â¿¡¼ (-1)!!=0!!=1!!=1À̵Ǵ°ǰ¡¿ä? 170p 9¹ø¿¡¼ À§ÀÇ Ç®ÀÌ ÇüÅ·ΠǮ¾îµµ ±¦Âú³ª¿ä?
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2017-09-20 |
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1¹ø° Áú¹® : °ã°è½ÂÀº ±×·¸°Ô Á¤ÀÇ ÇÕ´Ï´Ù.
2¹ø° Áú¹® : ±×·¯³»¿ä.
3¹ø° Áú¹® : ¿ªÇÔ¼öÀÇ ÀûºÐºÎºÐÀ» Âü°íÇϼ¼¿ä.(224ÂÊ Âü°í) °Å±â¿¡¼ À¯µµÇß½À´Ï´Ù.
»óÇѳ¢¸® °öÇؼ ÇÏÇѳ¢¸® °öÇÑ ÇÕÀ» »©ÁÖ¸é ¿µÀ̵Ǵ °ÍÀ» ¾Ë¼öÀÖÁÒ. |
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2017-09-19 |
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2017-09-19 |
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313p¿¡¼ 1. xÃà±âÁØ °ø½Ä¿¡¼ x°¡ (Y2+Y1)/2·Î ¹Ù²î°Ô µÇ³ª¿ä?
317p À¯ÇüÇнÀ1¿¡¼ Yc°¡ °è»êÀ» ÇÒ¶§±×³É ¿Ö 1-cos¼¼Å¸°¡ µÇ³ª¿ä? Yc´Â (1-cos¼¼Å¸/2)·Î °î¼±ÀÇ ÁßÁ¡À» ³ªÅ¸³»¾ßµÇÁö ¾Ê³ª¿ä?
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2017-09-20 |
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2017-09-20 |
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1¹ø Áú¹® : yÃàÀ¸·Î ȸÀüÇϴµ¥ xÀÇ ÇÔ¼ö·Î Ç¥Çö ÇÒ ¼ö ÀÖÁö¸¸ Áö±Ý ¹®Á¦°¡ yÀÇ º¯ÈÀ²À» ¹®Á¦À̹ǷΠy·Î Ç¥ÇöÇÑ °ÍÀÔ´Ï´Ù.
2¹ø Áú¹® : Áú¹®ÀÌ ¹«¾ùÀÌ ¹Ù²ï´Ù´Â °ÍÀΰ¡¿ä?
3¹ø Áú¹® : °î¼± À§ÀÇ Áß½ÉÀº °î¼± À§ÀÇ Á¡À̹ǷΠ±×·¸°Ô ³õÀº °ÍÀÔ´Ï´Ù. |
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2017-09-19 |
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265p 14¹ø¿¡¼ x=root2 cost y=sint·Î ³ªÅ¸³»´Âµ¥ t°¡ °¢µµÀÌ¸é ±ØÁÂǥó·³ x=rcost y=rsint·Î Ç¥Çö ÇØ¾ßµÇ´Â°Í ¾Æ´Ñ°¡¿ä?
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2017-09-20 |
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1¹ø° Áú¹® : ÀûºÐ °ø½Ä¿¡¼ ¹ÌºÐÇÑ °ÍÀÌ 2À̴ϱî. 2¸¦ ³ª´©¾î ÁÖ¾î¾ßÁÒ.
2¹ø° Áú¹® : f ÇÁ¶óÀÓÀÌ ¿µº¸´Ù Å©°Å³ª °°Àº °æ¿ì¸¦ ¸»ÇÏ´Â °ÍÀÔ´Ï´Ù.
3¹øÀç Áú¹® : Ÿ¿øÀÇ ¹æÁ¤½ÄÀÌ ÁÖ¾îÁ³À¸´Ï ±×·¸°Ô ġȯÇÏ´Â °ÍÀÌÁÒ. |
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2017-09-19 |
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2017-09-19 |
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°ÀÇ µè´øÁß ÀÌÇØ°¡ ¾È°¡¼ Áú¹®µå¸³´Ï´Ù. ¹®Á¦¿¡¼ ÁÖ¾îÁø ±Þ¼ö°¡ ¼ö·ÅÇÑ´Ù´Â °ÍÀÌ Á¶°ÇÀε¥, ÀϹÝÇ×ÀÌ nºÐÀÇ1ÀÎ ±Þ¼ö´Â ¹ß»êÇϱ⠶§¹®¿¡ »ç¿ëÇÒ ¼ö ¾ø´Â ÀϹÝÇ× ¾Æ´Ñ°¡¿ä?
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2017-09-20 |
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ÀϹÝÇ×À» ¾ðÁ¦ 1/nÀ» ÀÌ¿ëÇß³ª¿ä. ºÎÈ£°¡ ºÙ¾ú´Âµ¥¿ä...... |
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2017-09-19 |
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2017-09-19 |
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½ºÅ¸ÆíÀÔ¼öÇÐ ÀûºÐÇÐ 2:±Þ¼ö ±âÁ¸ÆÇ ¸ÅÀÏÅ×½ºÆ® 63ȸ ¸¶Áö¸· 11¹ø ´äÀÌ 1-ln2 °¡¾Æ´Ï¶ó -1-ln2 ¾Æ´Ñ°¡¿ä?
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2017-09-20 |
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2017-09-20 |
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2017-09-18 |
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minseo** |
µî·ÏÀÏ |
2017-09-18 |
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óÀ½ ÇÁ¸®Æнº·Î °áÁ¦Çؼ µé¾î ±¸±³ÀçÀÓÀ» ¾Ë·Áµå¸³´Ï´Ù. P,59 6¹ø¿¡¼ ¿Ö |x-2|<1 À̶ó°í ¾î¶»°Ô 1·Î °¡Á¤ÇÏ´ÂÁö ±Ã±ÝÇÕ´Ï´Ù. ¾Õ¿¡ ´ëÇ¥±âÃâÀ¯Çü¿¡¼´Â k·Î µÎ°í Ç®¾ú´Âµ¥ ¿Ö ÀÌ°Ç 1À̶ó°í ¾î¶»°Ô °¡Á¤Çؼ Ç®À̸¦ ÇÏÁÒ?
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2017-09-19 |
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¾ö¹ÐÇÑ ÀǹÌÀÇ ±ØÇÑÀº °è»ê Æí¸®»ó ±×·¸°Ô ³õÀº °ÍÀÔ´Ï´Ù.
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1535 |
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dudehs10** |
2017-09-17 |
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2017-09-17 |
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±×·¸´Ù¸é ÆòÇà»çº¯Çü °¢Á¡ A B C D¸¦ ¾î¶²°ÍÀ» º¸°í ¼ø¼¸¦ Á¤Çϴ°ǰ¡¿ä? °¢ 3Á¡ÀÇ (a,b,c) ÁÂÇ¥¸¸ ÁÖ¾îÁú°æ¿ì ÆòÇà»çº¯ÇüÀ» ¸¸µé¼ö ÀÖ´Â °æ¿ìÀÇ °¡Áö¼ö°¡ 3°¡Áö¶ó À߸𸣰ٽÀ´Ï´Ù
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2017-09-18 |
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µî·ÏÀÏ |
2017-09-18 |
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¼ø¼´ë·ÎÇÏ´Â °ÍÀÔ´Ï´Ù. ABCD¼ø¼´ë·Î ÆòÇà»çº¯ÇüÀ» ¸¸µé¸é µË´Ï´Ù. |
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1534 |
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2017-09-17 |
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2017-09-17 |
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½ºÅ¸ ÆíÀÔ¼öÇÐ ¼±Çü´ë¼ö º¤ÅÍ ¸ÅÀÏÅ×½ºÆ® ¹®Á¦ 50ȸ 7¹ø¹®Á¦¿¡¼ ÆòÇà»çº¯Çü ABCD¸¦ ¹è¿ÇÒ¶§ ¾Æ¹«·¸°Ô³ª ¹è¿ÇÏ°í BD º¤Å͸¦ ±¸Çߴµ¥¿ä °¢°¢ ÀÇ BDº¤ÅÍÀÇ °ªÀÌ °°´õ¶ó±¸¿ä ÀÌó·³ ¾Æ¹«·¸°Ô³ª ¹è¿Çسõ°í ±¸Çصµ µÇ´Â°Ç°¡¿ä?
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2017-09-17 |
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2017-09-17 |
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ÆòÇà»çº¯ÇüÀÇ ¹è¿Àº ¾Æ¹«·¸°Ô³ª ¹è¿ÇÏ´Â °ÍÀº ¾Æ´Õ´Ï´Ù. ¼ø¼´ë·ÎÇÏ´Â °ÍÀÔ´Ï´Ù. |
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rlaehdud49** |
2017-09-15 |
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ÀÛ¼ºÀÚ |
rlaehdud49** |
µî·ÏÀÏ |
2017-09-15 |
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1. 1-cos2x = 2sinÁ¦°öx ¶ó°í Çϼ̴µ¥ ÀÌ°Ô ¾î¶² °ø½ÄÀΰ¡¿ä? 2. 2sinÁ¦°öx = xÁ¦°öÀÎ°Ô x->0ÀÏ ¶§ º¯Çü°ø½ÄÀ롂 ÀÌÇØ°¡ ‰ç´Âµ¥, tanÁ¦°öx = xÁ¦°öÀÌ ¼º¸³µÈ´Ù¸é sin kx = kx½ÄÀÌ cos kx=kx, tan kx=kxµµ ¼º¸³ÀÌ µÇ´Â°Ç°¡¿ä? |
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2017-09-17 |
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2017-09-17 |
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1¹ø »ï°¢ÇÔ¼ö 2¹è°¢ °ø½ÄÀÔ´Ï´Ù. °¡¹ý°ø½ÄÀ» ÀÌ¿ëÇÏ¿© À¯µµÇÏ¸é µË´Ï´Ù. ¾Æ´Ï¸é À¯µµÇÏÁö ¸»°í ¾Ï±âÇÏ´Â °ÍÀÔ´Ï´Ù.
2¹ø sin kx = kx, tan kx=kxÀº ¼º¸³ÇÏÁö¸¸ cos kx=kx´Â ¼º¸³ÇÏÁö ¾Ê½À´Ï´Ù.
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2017-09-15 |
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2017-09-15 |
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·ÎÇÇÅ»ÀÇ Á¤¸®´Â 0/0²ÃÀÌ µÈ´Ù°í ¾Ë·ÁÁ̴ּµ¥, ¹«ÇÑ´ë/¹«ÇÑ´ë ²Ãµµ ·ÎÇÇÅ»·Î °¡´ÉÇÑ°¡¿ä? ½ÇÀü ¹®Á¦¿¡¼ ¹«ÇÑ´ë/¹«ÇÑ´ë ²Ã ¹®Á¦¸¦ ·ÎÇÇÅ»·Î Ǫ½Ã´Â °ÍÀ» º¸°í Áú¹® µå¸³´Ï´Ù~ |
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